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如何输入/排版化学反应方程式?

如何输入/排版化学反应方程式?

使用这个包:https://github.com/schang412/typst-whalogen

typst
#import "@preview/whalogen:0.2.0": ce

$ #ce("HCl + H2O -> H3O+ + Cl-") $
Typst compiled image
log
warning: comparing strings with types is deprecated
    ┌─ @preview/whalogen:0.2.0/lib.typ:187:9

187 │   assert(type(t) == "string", message: "ce: argument must be of type `string`")
    │          ^^^^^^^^^^^^^^^^^^^

    = hint: compare with the literal type instead
    = hint: this comparison will always return `false` in future Typst releases

warning: comparing strings with types is deprecated
    ┌─ @preview/whalogen:0.2.0/lib.typ:162:9

162 │       if type(r) != "string" {
    │          ^^^^^^^^^^^^^^^^^^^

    = hint: compare with the literal type instead
    = hint: this comparison will always return `false` in future Typst releases

warning: comparing strings with types is deprecated
   ┌─ @preview/whalogen:0.2.0/lib.typ:12:7

12 │     if type(item) != "string" {
   │        ^^^^^^^^^^^^^^^^^^^^^^

   = hint: compare with the literal type instead
   = hint: this comparison will always return `false` in future Typst releases

warning: this return unconditionally discards the content before it
   ┌─ @preview/whalogen:0.2.0/lib.typ:22:2

22 │   return result
   │   ^^^^^^^^^^^^^

   = hint: try omitting the `return` to automatically join all values

warning: comparing strings with types is deprecated
    ┌─ @preview/whalogen:0.2.0/lib.typ:210:7

210 │     if type(result_sub_str) == "string" {
    │        ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

    = hint: compare with the literal type instead
    = hint: this comparison will always return `false` in future Typst releases

warning: comparing strings with types is deprecated
    ┌─ @preview/whalogen:0.2.0/lib.typ:213:14

213 │     } else if type(result_sub_str) == "content" {
    │               ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

    = hint: compare with the literal type instead
    = hint: this comparison will always return `false` in future Typst releases
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